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N-(3-Methyl­phen­yl)benzamide

The asymmetric unit of the title compound, C(14)H(13)NO, contains four mol­ecules, which are linked through N—H⋯O hydrogen bonds into two symmetry-independent chains running parallel to [001] and [101]. The N—H and C=O bonds of the amide groups are trans oriented in all four mol­ecules. The mol­ecul...

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Detalles Bibliográficos
Autores principales: Gowda, B. Thimme, Foro, Sabine, Sowmya, B. P., Fuess, Hartmut
Formato: Texto
Lenguaje:English
Publicado: International Union of Crystallography 2008
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC2959694/
https://www.ncbi.nlm.nih.gov/pubmed/21581101
http://dx.doi.org/10.1107/S1600536808035186
Descripción
Sumario:The asymmetric unit of the title compound, C(14)H(13)NO, contains four mol­ecules, which are linked through N—H⋯O hydrogen bonds into two symmetry-independent chains running parallel to [001] and [101]. The N—H and C=O bonds of the amide groups are trans oriented in all four mol­ecules. The mol­ecules are not planar and both aromatic rings are twisted strongly relative to the plane of the amide group. The dihedral angle between the two benzene rings ranges from 70.6 (2) to 74.2 (2)°. The N—H bond is anti to the meta-methyl substituent in the aniline fragment in three of the four symmetry-independent mol­ecules. In the fourth mol­ecule, the aniline unit is disordered over two nearly coplanar positions; the anti and syn conformers occupy the same site in the crystal with equal probability.