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trans-Diaqua­bis­[2,5-bis­(pyridin-2-yl)-1,3,4-thia­diazole]nickel(II) bis­(tetra­fluoridoborate)

The bidentate 1,3,4-thia­diazole ligand, namely, 2,5-bis­(2-pyrid­yl)-1,3,4-thia­diazole (denoted L), untested as a polydentate ligand, has been found to form the monomeric title complex, [Ni(C(12)H(8)N(4)S)(2)(H(2)O)(2)](BF(4))(2). The complex shows an octa­hedral environment of the nickel cation i...

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Detalles Bibliográficos
Autores principales: Bentiss, Fouad, Capet, Frédéric, Lagrenée, Michel, Saadi, Mohamed, El Ammari, Lahcen
Formato: Online Artículo Texto
Lenguaje:English
Publicado: International Union of Crystallography 2011
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3212138/
https://www.ncbi.nlm.nih.gov/pubmed/22090840
http://dx.doi.org/10.1107/S1600536811026420
Descripción
Sumario:The bidentate 1,3,4-thia­diazole ligand, namely, 2,5-bis­(2-pyrid­yl)-1,3,4-thia­diazole (denoted L), untested as a polydentate ligand, has been found to form the monomeric title complex, [Ni(C(12)H(8)N(4)S)(2)(H(2)O)(2)](BF(4))(2). The complex shows an octa­hedral environment of the nickel cation in which the Ni(2+) ion is located on a center of symmetry, linked to two ligands and two water molecules. In this 1:2 complex (one metal for two organic ligands) each thia­diazole ligand uses one pyridyl and one thia­diazole N atom for chelate binding. In the second pyridyl substituent, the N atom is oriented towards the same direction as the S atom of the 1,3,4-thiadiazole ring. The mean plane of the thia­diazole and pyridyl rings linked to the nickel cation forms a dihedral angle with the other pyridine ring of 18.63 (8)°. The tetra­fluorido­borate ions can be regarded as free anions in the crystal lattice. Nevertheless, they are involved in an infinite two-dimensional network parallel to ([Image: see text]01) through O—H⋯F hydrogen bonds.