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N,N′-Bis(pyridin-2-yl)benzene-1,4-diamine–naphthalene (2/1)

The asymmetric unit of the title compound, C(10)H(8)·2C(16)H(14)N(4), consists of one mol­ecule of N,N′-bis­(pyridin-2-yl)benzene-1,4-diamine (PDAB) and one half of the centrosymmetric naphthalene mol­ecule. The PDAB mol­ecule adopts a non-planar conformation with an E configuration at the two parti...

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Detalles Bibliográficos
Autores principales: Wicher, Barbara, Gdaniec, Maria
Formato: Online Artículo Texto
Lenguaje:English
Publicado: International Union of Crystallography 2011
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3238953/
https://www.ncbi.nlm.nih.gov/pubmed/22199802
http://dx.doi.org/10.1107/S1600536811047519
Descripción
Sumario:The asymmetric unit of the title compound, C(10)H(8)·2C(16)H(14)N(4), consists of one mol­ecule of N,N′-bis­(pyridin-2-yl)benzene-1,4-diamine (PDAB) and one half of the centrosymmetric naphthalene mol­ecule. The PDAB mol­ecule adopts a non-planar conformation with an E configuration at the two partially double exo C N bonds of the 2-pyridyl­amine units. In the crystal, N—H⋯N hydrogen bonds between the PDAB mol­ecules generate a cyclic R (2) (2)(8) motif, leading to the formation of PDAB tapes extending along [100]. The tapes are arranged into (010) layers and the naphthalene mol­ecules are enclosed in cavities formed between the PDAB layers.