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1-[(Cyclo­propyl­meth­oxy)meth­yl]-6-(3,4-dimeth­oxy­benzyl)-5-ethyl-1,2,3,4-tetra­hydro­pyrimidine-2,4-dione ethanol hemisolvate

The asymmetric unit of the compound, C(20)H(26)N(2)O(5)·0.5C(2)H(5)OH, consists of two tetra­hydro­pyrimidine-2,4-dione mol­ecules and an ethanol mol­ecule. The pyrimidine rings are nearly planar (r.m.s. deviation = 0.006 Å in one mol­ecule and 0.009 Å in the other); the C atom at the 5-position dev...

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Detalles Bibliográficos
Autores principales: El-Brollosy, Nasser R., El-Emam, Ali A., Al-Deeb, Omar A., Ng, Seik Weng
Formato: Online Artículo Texto
Lenguaje:English
Publicado: International Union of Crystallography 2012
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3275033/
https://www.ncbi.nlm.nih.gov/pubmed/22346978
http://dx.doi.org/10.1107/S1600536811055693
Descripción
Sumario:The asymmetric unit of the compound, C(20)H(26)N(2)O(5)·0.5C(2)H(5)OH, consists of two tetra­hydro­pyrimidine-2,4-dione mol­ecules and an ethanol mol­ecule. The pyrimidine rings are nearly planar (r.m.s. deviation = 0.006 Å in one mol­ecule and 0.009 Å in the other); the C atom at the 5-position deviates by 0.083 (3) Å [0.064 (3) Å in the second mol­ecule] from the mean plane and the C atom at the 6-position by 0.034 (3) Å [0.082 (3) Å in the second mol­ecule]. In each mol­ecule, the benzene ring is nearly perpendicular to the pyrimidine ring, the dihedral angle is 88.51 (8)° in one mol­ecule and 84.70 (8)° in the other. The amino group of each tetra­hydro­pyrimidine-2,4-dione mol­ecule is a hydrogen-bond donor to the exocyclic O atom at the 2-position of an adjacent mol­ecule, the hydrogen bond generating an inversion dimer in each case. The ethanol mol­ecule forms a hydrogen bond to the meth­oxy O atom of one of two independent mol­ecules.