Cargando…

2-(Prop-2-enyloxy)benzamide

In the title mol­ecule, C(10)H(11)NO(2), the benzene ring forms dihedral angles of 33.15 (2) and 6.20 (2)° with the mean planes of the amide and propen­oxy groups, respectively. The amide –NH(2) group is oriented toward the propen­oxy substituent and forms a weak intra­molecular N—H⋯O hydrogen bond...

Descripción completa

Detalles Bibliográficos
Autores principales: Bugenhagen, Bernhard, Al Jasem, Yosef, Barkhad, Farah, Hindawi, Bassam al, Thiemann, Thies
Formato: Online Artículo Texto
Lenguaje:English
Publicado: International Union of Crystallography 2012
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3515263/
https://www.ncbi.nlm.nih.gov/pubmed/23284483
http://dx.doi.org/10.1107/S1600536812042250
Descripción
Sumario:In the title mol­ecule, C(10)H(11)NO(2), the benzene ring forms dihedral angles of 33.15 (2) and 6.20 (2)° with the mean planes of the amide and propen­oxy groups, respectively. The amide –NH(2) group is oriented toward the propen­oxy substituent and forms a weak intra­molecular N—H⋯O hydrogen bond to the propen­oxy O atom. The conformation of the propen­oxy group at the Csp (2)—Csp (3) and Csp (3)—O bonds is synperiplanar and anti­periplanar, respectively. In the crystal, N—H⋯O hydrogen bonds involving the amide groups generate C(4) and R (2) (3)(7) motifs that organize the mol­ecules into tapes along the a-axis direction. There are C—H⋯π inter­actions between the propen­oxy –CH(2) group and the aromatic system of neighboring mol­ecules within the tape. The mean planes of the aromatic ring and the propen­oxy group belonging to mol­ecules located on opposite sites of the tape form an angle of 83.16 (2)°.