Cargando…

Incompatible quartets, triplets, and characters

We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that...

Descripción completa

Detalles Bibliográficos
Autores principales: Shutters, Brad, Vakati, Sudheer, Fernández-Baca, David
Formato: Online Artículo Texto
Lenguaje:English
Publicado: BioMed Central 2013
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3694002/
https://www.ncbi.nlm.nih.gov/pubmed/23547777
http://dx.doi.org/10.1186/1748-7188-8-11
_version_ 1782274787273342976
author Shutters, Brad
Vakati, Sudheer
Fernández-Baca, David
author_facet Shutters, Brad
Vakati, Sudheer
Fernández-Baca, David
author_sort Shutters, Brad
collection PubMed
description We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that for every r≥2, there exists an incompatible set C of Ω(r(2))r-state characters such that every proper subset of C is compatible. This improves the previous lower bound of f(r)≥r given by Meacham (1983), and f(4)≥5 given by Habib and To (2011). For the case when r=3, Lam, Gusfield and Sridhar (2011) recently showed that f(3)=3. We give an independent proof of this result and completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern. Our lower bound on f(r) is proven via a result on quartet compatibility that may be of independent interest: For every n≥4, there exists an incompatible set Q of Ω(n(2)) quartets over n labels such that every proper subset of Q is compatible. We show that such a set of quartets can have size at most 3 when n=5, and at most O(n(3)) for arbitrary n. We contrast our results on quartets with the case of rooted triplets: For every n≥3, if R is an incompatible set of more than n−1 triplets over n labels, then some proper subset of R is incompatible. We show this bound is tight by exhibiting, for every n≥3, a set of n−1 triplets over n taxa such that R is incompatible, but every proper subset of R is compatible.
format Online
Article
Text
id pubmed-3694002
institution National Center for Biotechnology Information
language English
publishDate 2013
publisher BioMed Central
record_format MEDLINE/PubMed
spelling pubmed-36940022013-06-28 Incompatible quartets, triplets, and characters Shutters, Brad Vakati, Sudheer Fernández-Baca, David Algorithms Mol Biol Research We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that for every r≥2, there exists an incompatible set C of Ω(r(2))r-state characters such that every proper subset of C is compatible. This improves the previous lower bound of f(r)≥r given by Meacham (1983), and f(4)≥5 given by Habib and To (2011). For the case when r=3, Lam, Gusfield and Sridhar (2011) recently showed that f(3)=3. We give an independent proof of this result and completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern. Our lower bound on f(r) is proven via a result on quartet compatibility that may be of independent interest: For every n≥4, there exists an incompatible set Q of Ω(n(2)) quartets over n labels such that every proper subset of Q is compatible. We show that such a set of quartets can have size at most 3 when n=5, and at most O(n(3)) for arbitrary n. We contrast our results on quartets with the case of rooted triplets: For every n≥3, if R is an incompatible set of more than n−1 triplets over n labels, then some proper subset of R is incompatible. We show this bound is tight by exhibiting, for every n≥3, a set of n−1 triplets over n taxa such that R is incompatible, but every proper subset of R is compatible. BioMed Central 2013-04-01 /pmc/articles/PMC3694002/ /pubmed/23547777 http://dx.doi.org/10.1186/1748-7188-8-11 Text en Copyright © 2013 Shutters et al.; licensee BioMed Central Ltd. http://creativecommons.org/licenses/by/2.0 This is an Open Access article distributed under the terms of the Creative Commons Attribution License(http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
spellingShingle Research
Shutters, Brad
Vakati, Sudheer
Fernández-Baca, David
Incompatible quartets, triplets, and characters
title Incompatible quartets, triplets, and characters
title_full Incompatible quartets, triplets, and characters
title_fullStr Incompatible quartets, triplets, and characters
title_full_unstemmed Incompatible quartets, triplets, and characters
title_short Incompatible quartets, triplets, and characters
title_sort incompatible quartets, triplets, and characters
topic Research
url https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3694002/
https://www.ncbi.nlm.nih.gov/pubmed/23547777
http://dx.doi.org/10.1186/1748-7188-8-11
work_keys_str_mv AT shuttersbrad incompatiblequartetstripletsandcharacters
AT vakatisudheer incompatiblequartetstripletsandcharacters
AT fernandezbacadavid incompatiblequartetstripletsandcharacters