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Incompatible quartets, triplets, and characters
We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that...
Autores principales: | , , |
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Formato: | Online Artículo Texto |
Lenguaje: | English |
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BioMed Central
2013
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Materias: | |
Acceso en línea: | https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3694002/ https://www.ncbi.nlm.nih.gov/pubmed/23547777 http://dx.doi.org/10.1186/1748-7188-8-11 |
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author | Shutters, Brad Vakati, Sudheer Fernández-Baca, David |
author_facet | Shutters, Brad Vakati, Sudheer Fernández-Baca, David |
author_sort | Shutters, Brad |
collection | PubMed |
description | We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that for every r≥2, there exists an incompatible set C of Ω(r(2))r-state characters such that every proper subset of C is compatible. This improves the previous lower bound of f(r)≥r given by Meacham (1983), and f(4)≥5 given by Habib and To (2011). For the case when r=3, Lam, Gusfield and Sridhar (2011) recently showed that f(3)=3. We give an independent proof of this result and completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern. Our lower bound on f(r) is proven via a result on quartet compatibility that may be of independent interest: For every n≥4, there exists an incompatible set Q of Ω(n(2)) quartets over n labels such that every proper subset of Q is compatible. We show that such a set of quartets can have size at most 3 when n=5, and at most O(n(3)) for arbitrary n. We contrast our results on quartets with the case of rooted triplets: For every n≥3, if R is an incompatible set of more than n−1 triplets over n labels, then some proper subset of R is incompatible. We show this bound is tight by exhibiting, for every n≥3, a set of n−1 triplets over n taxa such that R is incompatible, but every proper subset of R is compatible. |
format | Online Article Text |
id | pubmed-3694002 |
institution | National Center for Biotechnology Information |
language | English |
publishDate | 2013 |
publisher | BioMed Central |
record_format | MEDLINE/PubMed |
spelling | pubmed-36940022013-06-28 Incompatible quartets, triplets, and characters Shutters, Brad Vakati, Sudheer Fernández-Baca, David Algorithms Mol Biol Research We study a long standing conjecture on the necessary and sufficient conditions for the compatibility of multi-state characters: There exists a function f(r) such that, for any set C of r-state characters, C is compatible if and only if every subset of f(r) characters of C is compatible. We show that for every r≥2, there exists an incompatible set C of Ω(r(2))r-state characters such that every proper subset of C is compatible. This improves the previous lower bound of f(r)≥r given by Meacham (1983), and f(4)≥5 given by Habib and To (2011). For the case when r=3, Lam, Gusfield and Sridhar (2011) recently showed that f(3)=3. We give an independent proof of this result and completely characterize the sets of pairwise compatible 3-state characters by a single forbidden intersection pattern. Our lower bound on f(r) is proven via a result on quartet compatibility that may be of independent interest: For every n≥4, there exists an incompatible set Q of Ω(n(2)) quartets over n labels such that every proper subset of Q is compatible. We show that such a set of quartets can have size at most 3 when n=5, and at most O(n(3)) for arbitrary n. We contrast our results on quartets with the case of rooted triplets: For every n≥3, if R is an incompatible set of more than n−1 triplets over n labels, then some proper subset of R is incompatible. We show this bound is tight by exhibiting, for every n≥3, a set of n−1 triplets over n taxa such that R is incompatible, but every proper subset of R is compatible. BioMed Central 2013-04-01 /pmc/articles/PMC3694002/ /pubmed/23547777 http://dx.doi.org/10.1186/1748-7188-8-11 Text en Copyright © 2013 Shutters et al.; licensee BioMed Central Ltd. http://creativecommons.org/licenses/by/2.0 This is an Open Access article distributed under the terms of the Creative Commons Attribution License(http://creativecommons.org/licenses/by/2.0), which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. |
spellingShingle | Research Shutters, Brad Vakati, Sudheer Fernández-Baca, David Incompatible quartets, triplets, and characters |
title | Incompatible quartets, triplets, and characters |
title_full | Incompatible quartets, triplets, and characters |
title_fullStr | Incompatible quartets, triplets, and characters |
title_full_unstemmed | Incompatible quartets, triplets, and characters |
title_short | Incompatible quartets, triplets, and characters |
title_sort | incompatible quartets, triplets, and characters |
topic | Research |
url | https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3694002/ https://www.ncbi.nlm.nih.gov/pubmed/23547777 http://dx.doi.org/10.1186/1748-7188-8-11 |
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