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Tenulin 0.25-hydrate, a sesquiterpene lactone isolated from Helenium amarum
The asymmetric unit of the title compound, C(17)H(22)O(5)·0.25H(2)O [systematic name: 2-hydroxy-2,2a,6,9a-tetramethyl-2a,4a,5,6,6a,9a,9b,9c-octahydro-2H-1,4-dioxadicyclopent[cd,f]azulene-3,9-dione 0.25-hydrate], a natural product isolated from Helenium amarum, contains two independent tenulin m...
Autores principales: | , , , |
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Formato: | Online Artículo Texto |
Lenguaje: | English |
Publicado: |
International Union of Crystallography
2013
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Materias: | |
Acceso en línea: | https://www.ncbi.nlm.nih.gov/pmc/articles/PMC3793741/ https://www.ncbi.nlm.nih.gov/pubmed/24109328 http://dx.doi.org/10.1107/S1600536813018369 |
Sumario: | The asymmetric unit of the title compound, C(17)H(22)O(5)·0.25H(2)O [systematic name: 2-hydroxy-2,2a,6,9a-tetramethyl-2a,4a,5,6,6a,9a,9b,9c-octahydro-2H-1,4-dioxadicyclopent[cd,f]azulene-3,9-dione 0.25-hydrate], a natural product isolated from Helenium amarum, contains two independent tenulin molecules and half a water molecule of crystallization situated on a twofold rotation axis. The hydroxy group of the hemiketal moiety is in a β-position. In the crystal, each water molecule interacts with four tenulin molecules via O—H⋯O hydrogen bonds. The two independent tenulin molecules (A and B) differ only in the character of their participation in hydrogen bonding. Specifically, while A is an acceptor of O(water)—H⋯O(A) and a donor of O(A)—H⋯O(B) hydrogen bonds, molecule B is an acceptor of the latter hydrogen bond and the donor of an O(B)—H⋯O(water) hydrogen bond. In the crystal, these O—H⋯O hydrogen bonds link the tenulin and water molecules into layers parallel to the ac plane. |
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