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How hard is it to tell which is a Condorcet committee?()

This paper establishes the computational complexity status for a problem of deciding on the quality of a committee. Starting with individual preferences over alternatives, we analyse when it can be determined efficiently if a given committee [Formula: see text] satisfies a weak (resp. strong) Condor...

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Detalles Bibliográficos
Autor principal: Darmann, Andreas
Formato: Online Artículo Texto
Lenguaje:English
Publicado: North-Holland 2013
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4376023/
https://www.ncbi.nlm.nih.gov/pubmed/25843993
http://dx.doi.org/10.1016/j.mathsocsci.2013.06.004
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author Darmann, Andreas
author_facet Darmann, Andreas
author_sort Darmann, Andreas
collection PubMed
description This paper establishes the computational complexity status for a problem of deciding on the quality of a committee. Starting with individual preferences over alternatives, we analyse when it can be determined efficiently if a given committee [Formula: see text] satisfies a weak (resp. strong) Condorcet criterion–i.e., if [Formula: see text] is at least as good as (resp. better than) every other committee in a pairwise majority comparison. Scoring functions used in classic voting rules are adapted for these comparisons. In particular, we draw the sharp separation line between computationally tractable and intractable instances with respect to different voting rules. Finally, we show that deciding if there exists a committee which satisfies the weak (resp. strong) Condorcet criterion is computationally hard.
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spelling pubmed-43760232015-04-01 How hard is it to tell which is a Condorcet committee?() Darmann, Andreas Math Soc Sci Article This paper establishes the computational complexity status for a problem of deciding on the quality of a committee. Starting with individual preferences over alternatives, we analyse when it can be determined efficiently if a given committee [Formula: see text] satisfies a weak (resp. strong) Condorcet criterion–i.e., if [Formula: see text] is at least as good as (resp. better than) every other committee in a pairwise majority comparison. Scoring functions used in classic voting rules are adapted for these comparisons. In particular, we draw the sharp separation line between computationally tractable and intractable instances with respect to different voting rules. Finally, we show that deciding if there exists a committee which satisfies the weak (resp. strong) Condorcet criterion is computationally hard. North-Holland 2013-11 /pmc/articles/PMC4376023/ /pubmed/25843993 http://dx.doi.org/10.1016/j.mathsocsci.2013.06.004 Text en © 2013 The Authors https://creativecommons.org/licenses/by/3.0/ Open Access under CC BY 3.0 (https://creativecommons.org/licenses/by/3.0/) license
spellingShingle Article
Darmann, Andreas
How hard is it to tell which is a Condorcet committee?()
title How hard is it to tell which is a Condorcet committee?()
title_full How hard is it to tell which is a Condorcet committee?()
title_fullStr How hard is it to tell which is a Condorcet committee?()
title_full_unstemmed How hard is it to tell which is a Condorcet committee?()
title_short How hard is it to tell which is a Condorcet committee?()
title_sort how hard is it to tell which is a condorcet committee?()
topic Article
url https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4376023/
https://www.ncbi.nlm.nih.gov/pubmed/25843993
http://dx.doi.org/10.1016/j.mathsocsci.2013.06.004
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