Formation of Gold(III) Alkyls from Gold Alkoxide Complexes

[Image: see text] The gold(III) methoxide complex (C(∧)N(∧)C)AuOMe (1) reacts with tris(p-tolyl)phosphine in benzene at room temperature under O abstraction to give the methylgold product (C(∧)N(∧)C)AuMe (2) together with O=P(p-tol)(3) ((C(∧)N(∧)C) = [2,6-(C(6)H(3)(t)Bu-4)(2)pyridine](2–)). Calculations show that this reaction is energetically favorable (ΔG = −32.3 kcal mol(–1)). The side products in this reaction, the Au(II) complex [Au(C(∧)N(∧)C)](2) (3) and the phosphorane (p-tol)(3)P(OMe)(2), suggest that at least two reaction pathways may operate, including one involving (C(∧)N(∧)C)Au(•) radicals. Attempts to model the reaction by DFT methods showed that PPh(3) can approach 1 to give a near-linear Au–O–P arrangement, without phosphine coordination to gold. The analogous reaction of (C(∧)N(∧)C)AuOEt, on the other hand, gives exclusively a mixture of 3 and (p-tol)(3)P(OEt)(2). Whereas the reaction of (C(∧)N(∧)C)AuOR (R = Bu(t), p-C(6)H(4)F) with P(p-tol)(3) proceeds over a period of hours, compounds with R = CH(2)CF(3), CH(CF(3))(2) react almost instantaneously, to give 3 and O=P(p-tol)(3). In chlorinated solvents, treatment of the alkoxides (C(∧)N(∧)C)AuOR with phosphines generates [(C(∧)N(∧)C)Au(PR(3))]Cl, via Cl abstraction from the solvent. Attempts to extend the synthesis of gold(III) alkoxides to allyl alcohols were unsuccessful; the reaction of (C(∧)N(∧)C)AuOH with an excess of CH(2)=CHCH(2)OH in toluene led instead to allyl alcohol isomerization to give a mixture of gold alkyls, (C(∧)N(∧)C)AuR′ (R′ = −CH(2)CH(2)CHO (10), −CH(2)CH(CH(2)OH)OCH(2)CH=CH(2) (11)), while 2-methallyl alcohol affords R′ = CH(2)CH(Me)CHO (12). The crystal structure of 11 was determined. The formation of Au–C instead of the expected Au–O products is in line with the trend in metal–ligand bond dissociation energies for Au(III): M–H > M–C > M–O.