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Optimal charging of fractional-order circuits with Cuckoo search
INTRODUCTION: Optimal charging of RC circuits is a well-studied problem in the integer-order domain due to its importance from economic and system temperature hazards perspectives. However, the fractional-order counterpart of this problem requires investigation. OBJECTIVES: This study aims to find a...
Autores principales: | , , , |
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Formato: | Online Artículo Texto |
Lenguaje: | English |
Publicado: |
Elsevier
2020
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Materias: | |
Acceso en línea: | https://www.ncbi.nlm.nih.gov/pmc/articles/PMC8408332/ https://www.ncbi.nlm.nih.gov/pubmed/34484831 http://dx.doi.org/10.1016/j.jare.2020.11.014 |
Sumario: | INTRODUCTION: Optimal charging of RC circuits is a well-studied problem in the integer-order domain due to its importance from economic and system temperature hazards perspectives. However, the fractional-order counterpart of this problem requires investigation. OBJECTIVES: This study aims to find approximate solutions of the most energy-efficient input charging function in fractional-order RC circuits. METHODS: This paper uses a meta-heuristic optimization technique called Cuckoo search optimizer to attain the maximum charging efficiency of three common fractional-order RC circuits. An analytical expression of the fractional capacitor voltage is suggested such that it satisfies the boundary conditions of the optimal charging problem. The problem is formulated as a fractional-order calculus of variations problem with compositional functional. The numerical solutions are obtained with the meta-heuristic optimization algorithm’s help to avoid the complexities of the analytical approach. RESULTS: he efficiency surfaces and input voltage charging curves are discussed for fractional-order in the range [Formula: see text]. CONCLUSION: The optimized charging function can approximate the optimal charging curve using at most 4 terms. The charging time and the resistive parameters have the most dominant effect on charging efficiency at constant fractional-order [Formula: see text]. |
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