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Adsorption of Helium and Hydrogen on Triphenylene and 1,3,5-Triphenylbenzene

The adsorption of helium or hydrogen on cationic triphenylene (TPL, C(18)H(12)), a planar polycyclic aromatic hydrocarbon (PAH) molecule, and of helium on cationic 1,3,5-triphenylbenzene (TPB, C(24)H(18)), a propeller-shaped PAH, is studied by a combination of high-resolution mass spectrometry and c...

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Detalles Bibliográficos
Autores principales: Bergmeister, Stefan, Kollotzek, Siegfried, Calvo, Florent, Gruber, Elisabeth, Zappa, Fabio, Scheier, Paul, Echt, Olof
Formato: Online Artículo Texto
Lenguaje:English
Publicado: MDPI 2022
Materias:
Acceso en línea:https://www.ncbi.nlm.nih.gov/pmc/articles/PMC9370105/
https://www.ncbi.nlm.nih.gov/pubmed/35956887
http://dx.doi.org/10.3390/molecules27154937
Descripción
Sumario:The adsorption of helium or hydrogen on cationic triphenylene (TPL, C(18)H(12)), a planar polycyclic aromatic hydrocarbon (PAH) molecule, and of helium on cationic 1,3,5-triphenylbenzene (TPB, C(24)H(18)), a propeller-shaped PAH, is studied by a combination of high-resolution mass spectrometry and classical and quantum computational methods. Mass spectra indicate that He(n)TPL(+) complexes are particularly stable if n = 2 or 6, in good agreement with the quantum calculations that show that for these sizes, the helium atoms are strongly localized on either side of the central carbon ring for n = 2 and on either side of the three outer rings for n = 6. Theory suggests that He(14)TPL(+) is also particularly stable, with the helium atoms strongly localized on either side of the central and outer rings plus the vacancies between the outer rings. For He(n)TPB(+), the mass spectra hint at enhanced stability for n = 2, 4 and, possibly, 11. Here, the agreement with theory is less satisfactory, probably because TPB(+) is a highly fluxional molecule. In the global energy minimum, the phenyl groups are rotated in the same direction, but when the zero-point harmonic correction is included, a structure with one phenyl group being rotated opposite to the other two becomes lower in energy. The energy barrier between the two isomers is very small, and TPB(+) could be in a mixture of symmetric and antisymmetric states, or possibly even vibrationally delocalized.